Deleting Duplicate data from MySQL database in PHP

I am making an application from data import from excel file. In application user may be import several time or different file may be contains same data. But I always need unique data row from other calculation. So I badly need delete Duplicated row from table after importing data from excel file.
For Solve this problem I found couple of solution on web.

Solution:1 If table contain a primary key
Table :

 
  create table TableName1 (
  ID int(11) NOT NULL AUTO_INCREMENT ,
  CODE varchar(20) , 
  NAME varchar(100) ,
  PRIMARY KEY (ID)
  ) 
  

Data

ID	CODE	NAME
1	A1001	Mahfuz
2	A1002	Lemon
3	A1001	Mahfuz
4	A1002	Lemon
5	A1003	Babu

 <?php
 $conn = mysql_connect("localhost", "mysql_user", "mysql_password");
if (!$conn) {
    echo "Unable to connect to DB: " . mysql_error();
    exit;
}
if (!mysql_select_db("mydbname")) {
    echo "Unable to select mydbname: " . mysql_error();
    exit;
}



$sql = "DELETE FROM TableName1
USING TableName1, TableName1 AS vtable
WHERE vtable.id > TableName1.id
AND TableName1.CODE = vtable.CODE
And TableName1.NAME = vtable.NAME";

mysql_query($sql);

$sql_check = "SELECT NAME,
COUNT(NAME) AS NumOccurrences
FROM TableName1
GROUP BY NAME
HAVING ( COUNT(NAME) > 1 )";
$result = mysql_query($sql_check);

if (mysql_num_rows($result) == 0) {
    echo "No Duplicate rows found";
}
?>

Solution 2: If table have no primary key
Table :

 create table TableName1 ( 
  CODE varchar(20) , 
  NAME varchar(100)
)

Data

CODE	NAME
A1001	Mahfuz
A1002	Lemon
A1001	Mahfuz
A1002	Lemon
A1003	Babu

 <?php

$conn = mysql_connect("localhost", "mysql_user", "mysql_password");
if (!$conn) {
    echo "Unable to connect to DB: " . mysql_error();
    exit;
}
if (!mysql_select_db("mydbname")) {
    echo "Unable to select mydbname: " . mysql_error();
    exit;
}



$sql1 = " CREATE TEMPORARY TABLE temp_TableName1 as select * from TableName1 group By code,name";

mysql_query($sql1);

$sql2 = " TRUNCATE TABLE TableName1 ";

mysql_query($sql2);

$sql3 = " INSERT INTO TableName1 SELECT * FROM temp_TableName1 ";

mysql_query($sql3);

$sql_check = "SELECT NAME,
COUNT(NAME) AS NumOccurrences
FROM TableName1
GROUP BY NAME
HAVING ( COUNT(NAME) > 1 )";
$result = mysql_query($sql_check);

if (mysql_num_rows($result) == 0) {
    echo "No Duplicate rows found";
}

?>

Difference between mysql_fetch_assoc, mysql_fetch_row,mysql_fetch_object and mysql_fetch_array

Definition :

mysql_fetch_array():-

Fetch a result row as an associative array, a numeric array, or both by default it fetches both.

Returns an array of strings that corresponds to the fetched row, or FALSE  if there are no more rows. The type of returned array depends on how result_typeis defined. By using MYSQL_BOTH (default), you'll get an array with both associative and number indices. Using MYSQL_ASSOC, you only get associative indices (as mysql_fetch_assoc() works), using MYSQL_NUM, you only get number indices (as mysql_fetch_row() works).

mysql_fetch_row() :-

Get a result row as an numeric array

Returns an numerical array of strings that corresponds to the fetched row, or FALSE if there are no more rows.
mysql_fetch_row() fetches one row of data from the result associated with the specified result identifier. The row is returned as an array.

mysql_fetch_object :-

Fetch a result row as an object

Returns an object with string properties that correspond to the fetched row, orFALSE;if there are no more rows.

mysql_fetch_assoc() :-

Fetch a result row as an associative array

Returns an associative array that corresponds to the fetched row and moves the internal data pointer ahead. mysql_fetch_assoc() is equivalent to callingmysql_fetch_array() with MYSQL_ASSOC for the optional second parameter. It only returns an associative array.

Example:

<?php

$conn = mysql_connect("localhost", "mysql_user", "mysql_password");

if (!$conn) {
    echo "Unable to connect to DB: " . mysql_error();
    exit;
}
  
if (!mysql_select_db("mydbname")) {
    echo "Unable to select mydbname: " . mysql_error();
    exit;
}

$sql = "SELECT id as userid, fullname, userstatus 
        FROM   sometable
        WHERE  userstatus = 1";

$result = mysql_query($sql);

if (!$result) {
    echo "Could not successfully run query ($sql) from DB: " . mysql_error();
    exit;
}

if (mysql_num_rows($result) == 0) {
    echo "No rows found, nothing to print so am exiting";
    exit;
}

// While a row of data exists, put that row in $row as an associative array
// Note: If you're expecting just one row, no need to use a loop
// Note: If you put extract($row); inside the following loop, you'll
//       then create $userid, $fullname, and $userstatus
while ($row = mysql_fetch_array ($result)) {
    echo $row[0];
    echo $row[1];
    echo $row[2];
}

while ($row = mysql_fetch_array ($result)) {
    echo $row["userid"];
    echo $row["fullname"];
    echo $row["userstatus"];
}

while ($row = mysql_fetch_array ($result)) {
    echo $row[0];
    echo $row["fullname"];
    echo $row[2];
}

while ($row = mysql_fetch_row($result)) {
    echo $row[0];
    echo $row[1];
    echo $row[2];
}

while ($row = mysql_fetch_object($result)) {
    echo $row->userid;
    echo $row->fullname;
    echo $row->userstatus;
}

while ($row = mysql_fetch_assoc($result)) {
    echo $row["userid"];
    echo $row["fullname"];
    echo $row["userstatus"];
}


mysql_free_result($result);
?>

Performance

Using both  mysql_fetch_array() and mysql_fetch_assoc()  is not significantly slower than using mysql_fetch_row(),

Speed-wise, the function is identical to mysql_fetch_array(), and almost as quick as mysql_fetch_row() (the difference is insignificant).

mysql_fetch_object() is similar to mysql_fetch_array(), with one difference - an object is returned, instead of an array. Indirectly, that means that you can only access the data by the field names, and not by their offsets (numbers are illegal property names).

How can I Confirm to leave the page when someone insert / editing a form in php

I'm creating an PHP web application and I want to implement logic to warn the user when they are navigating away from a page they've edited. I found some solution on the web .


For this solution we bound a JavaScript function to the unload event:

 window.onbeforeunload  

I use following code in different aspect
For all type of Input .

$(document).ready(function() { 
    $(":input").one("change", function() { 
        window.onbeforeunload = function() { return 'You will lose data changes.'; } 
    }); 
    $('.noWarn').click(function() { window.onbeforeunload = null; }); 
});

Your input elements probably do not exist when the code is executed. Try using the .live function to detect changes on all input elements, or wrap your code in a $(document).ready() handler.

$('input').live("change", function () {
    window.onbeforeunload = function () { return "Your changes have not been saved?" };
});

For specific input type on body

$(document).ready(function() {

    //----------------------------------------------------------------------
    // Don't allow us to navigate away from a page on which we're changed
    //  values on any control without a warning message.  Need to class our 
    //  save buttons, links, etc so they can do a save without the message - 
    //  ie. CssClass="noWarn"
    //----------------------------------------------------------------------
    $('input:text,input:checkbox,input:radio,textarea,select').one('change', function() {
        $('BODY').attr('onbeforeunload',
        "return 'Leaving this page will cause any unsaved data to be lost.';");
    });

    $('.noWarn').click(function() { $('BODY').removeAttr('onbeforeunload'); });

});

Best solution for form base: In this solution if you are change something in your form then when you want to leave from this page user can get a message for confirmation.

function formIsDirty(form)
      {
          for (var i = 0; i < form.elements.length; i++)
          {
              var element = form.elements[i];
              var type = element.type;
              if (type == "checkbox" || type == "radio")
              {
                  if (element.checked != element.defaultChecked)
                  {
                      return true;
                  }
              }
              else if (type == "hidden" || type == "password" || type == "text" ||
                       type == "textarea")
              {
                  if (element.value != element.defaultValue)
                  {
                      return true;
                  }
              }
              else if (type == "select-one" || type == "select-multiple")
              {
                  for (var j = 0; j < element.options.length; j++)
                  {
                      if (element.options[j].selected !=
                          element.options[j].defaultSelected)
                      {
                          return true;
                      }
                  }
              }
          }
          return false;
      }

      window.onbeforeunload = function(e)
      {
          e = e || window.event;  
// You put your from ID
          if (formIsDirty(document.forms['fromid'])) 
          {
              // For IE and Firefox
              if (e)
              {
                  e.returnValue = "You have unsaved changes.";
              }
              // For Safari
              return "You have unsaved changes.";
          }
      };